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Rules:



[n] = n

[n, 0] = n+1

[n, 1] = n+2

[n, x] = n+(x+1)

[n, 1, 2] = [n, n]

[n, 2, 2] = [n, n+1]

[n, x, 2] = [n, (n+(x-1))] = [n, [n, x-2]]

[n, 1, 3] = [n, n, 2] = [n, (2n-1)] = n+2n = 3n

That's it for now :D

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