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Revision as of 17:00, 2 April 2021
(WORK IN PROGRESS)
See:
Original Part IV, a stupid attempt at an extension that will be ignored for this purpose
Let's get down to business. In the original Part IV, I defined <A,A> as an operator and allowed for operations on <A,A>. That sucked. I have a better idea.
A1 = A
<a,b>★An = <a,a>★<An-1,An-1>b (exponent denotes concatenation, NOT an operator)
An will still evaluate to <An-1,An-1>b if placed after any number of up-arrows.
Definition may change.
Recursive progression
<a,b>A2 ≈ ψ(Ωω)
<a,b>A2A ≈ ψ(Ωω)+1
<a,b>A2A2 ≈ ψ(Ωω)2
<a,b>A2A ≈ ψ(Ωω)×ω
<a,b>A2A↑↑A ≈ ψ(Ωω)×ε0
<a,b>A2A2 ≈ ψ(Ωω)2
<a,b>A2A2A ≈ ψ(Ωω)ω
<a,b>A2A2A↑↑A ≈ ψ(Ωω)ε0
<a,b>A2↑↑3 ≈ ψ(Ωω)↑↑2
<a,b>A2↑↑n ≈ ψ(Ωω)↑↑(n-1)
<a,b>A2↑↑A ≈ ψ(Ωω+Ω)
<a,b>A2↑↑A↑↑A ≈ ψ(Ωω+Ω2)
<a,b>A2↑↑A↑↑↑A ≈ ψ(Ωω+Ω2)
<a,b>A2↑↑A↑↑↑↑A ≈ ψ(Ωω+Ω3)
<a,b>A2↑↑A ↑A A ≈ ψ(Ωω+Ωω)
<a,b>A2↑↑<A,A>AAA ≈ ψ(Ωω+ΩΩ)
<a,b>A2↑↑<A,A>A↑↑A ≈ ψ(Ωω+Ω2)
<a,b>A2↑↑<A,A><A,A>AAA ≈ ψ(Ωω+Ω3)
<a,b>A2↑↑A2 ≈ ψ(Ωω×2)
<a,b>(A2↑↑A2)↑↑A ≈ ψ(Ωω×2+1)
<a,b>(A2↑↑A2)↑↑A↑↑A ≈ ψ(Ωω×2+Ω)
<a,b>(A2↑↑A2)↑↑A2 = A2↑↑A2A ≈ ψ(Ωω×3)
<a,b>A2↑↑A2AA ≈ ψ(Ωω×ω)
<a,b>A2↑↑A2(A↑↑A) ≈ ψ(Ωω×Ω)
<a,b>A2↑↑A2A2 ≈ ψ(Ωω2)
<a,b>A2↑↑A2A ≈ ψ(Ωωω)
<a,b>A2↑↑A2A↑↑A ≈ ψ(ΩωΩ)
<a,b>A2↑↑A2A2 ≈ ψ(ΩωΩω)
<a,b>A2↑↑A2↑↑A ≈ ψ(Ωω+1)
<a,b>A2↑↑A2↑↑AA ≈ ψ(Ωω2)
<a,b>A2↑↑A2↑↑A↑↑A ≈ ψ(ΩΩ)
<a,b>A2↑↑A2↑↑A↑↑↑A ≈ ψ(ΩΩ2)
<a,b>A2↑↑A2↑↑<A,A>AAA ≈ ψ(ΩΩ2)
<a,b>A2↑↑A2↑↑A2 ≈ ψ(ΩΩω)
<a,b>A2↑↑A2↑↑A2↑↑A ≈ ψ(ΩΩω+1)
<a,b>A2↑↑A2↑↑A2↑↑A2 ≈ ψ(ΩΩΩω)
<a,b>A2↑↑↑A ≈ ψ(OFP)
I don't know how to express ordinals beyond ψ(OFP) using an efficient notation. Until then I will use capital epsilon (E) to denote the αth omega fixed point as Eα, and continue using the Veblen hierarchy but with capital Greek letters. This is most likely ill-defined and should be left up to interpretation.
<a,b>A2↑↑↑A ≈ ψ(E0)
<a,b>(A2↑↑↑A)↑↑A2 ≈ ψ(ΩE0)
<a,b>A2↑↑↑AA ≈ ψ(E1)
<a,b>A2↑↑↑AA ≈ ψ(ψI(Eω)
<a,b>A2↑↑↑A↑↑A ≈ ψ(Eε0)
<a,b>A2↑↑↑A↑↑↑A ≈ ψ(Eζ0)
<a,b>A2↑↑↑A ↑A A ≈ ψ(Eφ(ω,0))
<a,b>A2↑↑↑<A,A>AAA ≈ ψ(Eψ(Ω2))
<a,b>A2↑↑↑A2 ≈ ψ(Eψ(Ωω))
<a,b>A2↑↑↑A2A ≈ ψ(Eψ(Ωω)+1)
<a,b>A2↑↑↑A2↑↑↑A ≈ ψ(Eψ(E0))
<a,b>A2↑↑↑↑A ≈ ψ(EΩ), the first fixed point of α ↦ ψ(Eα)
<a,b>(A2↑↑↑↑A)↑↑↑A2 ≈ ψ(EΩ+1)
<a,b>A2↑↑↑↑AA ≈ ψ(EΩ+ω)
<a,b>A2↑↑↑↑A↑↑A ≈ ψ(EΩ+ε0)
<a,b>A2↑↑↑↑A2 ≈ ψ(EΩ+ψ(E0))
<a,b>A2↑↑↑↑A2AA ≈ ψ(EΩ2)
<a,b>A2↑↑↑↑A2A2 ≈ ψ(EΩ×ψ(E0))
<a,b>A2↑↑↑↑A2A ≈ ψ(EΩ2)
<a,b>A2↑↑↑↑A2↑↑↑A ≈ ψ(EE0)
<a,b>A2↑↑↑↑A2↑↑↑↑A ≈ ψ(EEΩ)
<a,b>A2↑↑↑↑↑A ≈ ψ(Z0)
<a,b>A2↑↑↑↑↑AA ≈ ψ(Z1)
<a,b>A2↑↑↑↑↑A2 ≈ ψ(Zψ(Ωω))
<a,b>A2↑↑↑↑↑A2AA ≈ ψ(ZΩ)
<a,b>A2↑↑↑↑↑A2↑↑↑A ≈ ψ(ZE0)
<a,b>A2↑↑↑↑↑A2↑↑↑↑↑A ≈ ψ(ZZ0)
<a,b>A2↑↑↑↑↑↑A ≈ ψ(H0)
<a,b>A2↑↑↑↑↑↑A2 ≈ ψ(Hψ(Ωω))
<a,b>A2↑↑↑↑↑↑↑A ≈ ψ(Φ(4,0))
<a,b>A2 ↑A A ≈ ψ(Φ(ω,0))
<a,b>A2 ↑A ↑A A A ≈ ψ(Φ(φ(ω,0),0))
<a,b>A2 ↑A2 A ≈ ψ(Φ(ψ(Ωω),0))
<a,b>A2 ↑A2 ↑A A A ≈ ψ(Φ(ψ(Φ(ω,0)),0))
As you can see, A2 is a very powerful extension by itself. But A3 diagonalizes over it just the same.
<a,b>A3 ≈ ψ(Φ(Ω,0)), the first fixed point of α ↦ ψ(Φ(α,0)).
WIP article