User blog comment:Edwin Shade/Understanding The Infinite/@comment-25601061-20171109021425/@comment-80.98.179.160-20171113174744

No. It's ω2+3ω, also written as ω2+ω3 (those who assume 2ω=ω write so).

So, (ω+3)ω=ω2+3ω also ω2+ω3 (assuming 2ω=ω)

But since $$2x=x$$ implies $$x=0$$, x can't be ω unless ω=0.