User blog comment:P進大好きbot/Elementary Large Number/@comment-30754445-20181118000005/@comment-30754445-20181118172354

"I guess that you correctly understood the computation, but just miscalculated (or mistyped) a little."

Yeah.

I did it in reverse (doubled 13 and added 1, instead of halving (13+1)). I have absolutely no idea why I did that. I've actually written the formula down the formula for this, before I took my "guess":

Ord(2(n+1)/2)=ωOrd(n)

And I don't really know why this formula is true for your system. I just guessed it works, because it was the simplest function that fits your table of-values.

BTW I still have absolutely no clue how ordinal addition works with your system.

"I think that such an explanation might be helpful for googologists who know either one of them."

It probably is, but you won't find many such googologists here. Why add yet another confusing term to topic that's already difficult?