User blog comment:Simplicityaboveall/Insanely Fast-Growing Functions/@comment-25912386-20171111063151

Hi PsiCubed2  !

Thanks for your comments. Now that I have some free time, I will examine them seriously.

What your answered to  Denis Maksudov is an interesting comment (stated below) and I will have to find a way to solve that issue

" Denis, note that Joe  did  diagonalize once.

The transition from h to H is exactly the kind of process you've described.

That's why H(11) is, indeed, comparable to fω+1(10) rather than f11(10).

From here on, however, H continues by simple recursion. There's no second diagonalization, so H(21) is comparable only to fω+11(10) rather than fω×2+1(10). "

For now, I would like to tell you guys that I have always try to make things as simple as possible (but not simpler as would have said Einstein !) especially when I teach Physics to my students. I do strongly believe that laymen can understand the way very large numbers are constructed without a profound understanding of Set Theory and very very large ordinals. I do also believe that "Googology" should be made as simple as possible for the popularity of this great site. You see guys, being too technical or theoretical is not necessarily a good thing.

What is the use of creating something mathematically great which can be understood by only a few people ?

I believe that my work is simple enough for  "ordinary" people to understand. And, this is where I see achievement. I understand it needs some corrections as you two mentionned in your comments. Thanks for that !

PsiCubed2 ! I will definitely consider your last comments and I will try to make the necessary corrections. You and Denis Maksudov are definitely doing a great job in Googology. You are really genuine maths lovers. Sincerely wishing you the best for your future work.

PS: There are things I do not quite understand and I hope you will answer some of the questions I have in mind. For example, what is the value of Rayo(n) for n equals 1 to 10 ?

See you soon

God bless

Best Regards,

Joe



