User blog comment:Wythagoras/Dollar function: final version/@comment-5029411-20131117220000

{1}(1) = ([0])...([0])

{1}(n+1) = ([0])...([0]){1}(n)

{1}{1} = {1}([0])...([0])

{2} = ([0]){1}([0])...([0]){1}([0])

{2}(n+1) = ([0]){1}([0])...([0]){1}([0]){2}(n)

{3} = ([0]){2}([0])...([0]){2}([0])

{n+1} = ([0]){n}([0])...([0]){n}([0])

{0}{1} = {...{[0]}...}

{0}{n+1} = {...{[0]}{n}...}{n}

{{{sub|2}}1} = {a}...{a}

{{{sub|2}}1}{n+1} = {a}...{a}{{{sub|2}}1}{n}