User blog comment:XXxKennyDashxXx/A NEW NOTATION! HBAN./@comment-99.185.0.100-20150806234146

I have a better defined variation:


 * 1) is any square brackets

&[a] = 10^^a

&[a][b]# = &[a-1][&[a][b-1]#]#

&[a][1]# = a

&[1]# = &#

And I also think I figured out how to define the first part of EHBAN. @ is any curly braces.

&[a] = 10^^a

&@{1}[a] = &@[a][a]...[a][a] with a [a]s

&@{n}[a] = &@{n-1}{n-1}...{n-1}{n-1}[a] with a {n-1}s

&@[a][b]# = &@[a-1][&@[a][b-1]#]#

&@[a][1]# = a

&@[1]# = &@#