User:Googleaarex/Aarex's 100-Tier Illion

Tier 1, 2, and 3 -illion is 4-Tier Bowers' illion.

Tier 4
Let Marcillion = I(I(I(1000))+1), Marco-untillion = I(I(I(1000))+2), Marco-duotillion = I(I(I(1000))+3), etc.

Then, Duo-marcillion = I(I(I(1000))*2+1), Tre-marcillion = I(I(I(1000))*3+1), etc.

Next, Macra-millillion = I(I(I(1000)+1)+1), Macra-micrillion = I(I(I(1000)+2)+1), etc.

Then, Micre-macrillion = I(I(I(1000)*2)+1), Nane-macrillion = I(I(I(1000)*3)+1), etc.

Next, Macri-killillion = I(I(I(1001))+1), Macri-megillion = I(I(I(1002))+1), etc.

Then, Megemacrillion = I(I(I(2000))+1), Gigemacrillion = I(I(I(3000))+1), etc.

We have Aprillion = I(I(I(1000000))+1), Maillion = I(I(I(1000000000))+1), Junillion = I(I(I(I(4)))+1), Julillion = I(I(I(I(5)))+1), Augusillion = I(I(I(I(6)))+1), Septembeillion = I(I(I(I(7)))+1), Octembeillion = I(I(I(I(8)))+1), and Novembeillion = I(I(I(I(9)))+1).

Then Decembeillion = I(I(I(I(10)))+1), Undecembeillion = I(I(I(I(10)))+1), Doedecembeillion = I(I(I(I(10)))+1), etc. So I(I(I(I(N)))+1), is equal to M-embeillion, where M is n-th Bowers' prefix.

The limit of tier 4 -illion is Millembeillion.