User blog comment:Boris Huller/need some help/@comment-30869823-20180514154224

Prove your function out grows a certain fast growing hierachy function, is so your function grows at least as fast as that function (the reverse applies aswell). If you can prove \( f_\alpha(n)f_0(n) \) \( A(2,n)>f_1(n) \) \( A(3,n)>f_2(n) \) \( A(m+1,n)>f_m(n) \) \( F(n)=A(n+1,n)>f_n(n)>f_\omega(n) \)

So the growth rate of the Ackermannfunction is ω