User blog:Kel47/Kel's Extended Illions

First, let's define an Illion function I(x) = 10^(3x+3) (short scale)

Million = I(1) = 10^(3+3) = 10^6 Centillion = I(100) = 10^(3*100+3) = 10^303

This system uses the standard latin based names up to a Millillion.

Then we can do things like:

Millionillion = I(I(1) = I(10^6) = 10^3,000,003

In this naming system, we will have:

Latin Prefix + Greek Prefix + "illion"

The Latin Prefix tells us the number that goes in the innermost I function. The Greek Prefix tells us how many times to plug I into itself

In other words, A-B-illion = I(I(I(...I(A)))..) B times

Examples: undi-illion A = 1 B = 2 I(I(1) = 10^3,000,003

centitri-illion A = 100 B = 3 I(I(I(100))) = I(I(10^303) I(10^(3*10^303 + 3)) ~ I(10^10^303) ~ 10^10^10^303

quadriheptillion A = 4 B = 7 I(I(I(I(I(I(I(4))))))) ~ (10^^7)^15

quinkillillion A=5 B=1000 I(I(I...I(I(5))..) 1000 times ~ (10^^1000)^18