User blog comment:Nayuta Ito/Introduction To Bashicu Matrix System/@comment-24061664-20151213060253

Thank you for explanation.

By using this site for calculation http://gyafun.jp/ln/basmat.cgi I found a mistake in example #2.

Here is how it works.

f(n)=4 G=nothing,B=(0,0,0)(1,1,1)(2,2,2)(3,3,3),N=(4,2,1) //(1,1,1)N(4,2,1) and (0,0,0)<(4,2,1) Δ=(4,2,0) // L=(0,0,0) and N=(4,2,1) B(0)=(0,0,0)(1,1,1)(2,2,2)(3,3,3) B(1)=(4,2,0)(5,3,1)(6,4,2)(7,5,3) B(2)=(8,4,0)(9,5,1)(10,6,2)(11,7,3) B(3)=(12,6,0)(13,7,1)(14,8,2)(15,9,3) B(4)=(16,8,0)(17,9,1)(18,10,2)(19,11,3) Therefore, (0,0,0)(1,1,1)(2,2,2)(3,3,3)(4,2,1)[2] changes into (0,0,0)(1,1,1)(2,2,2)(3,3,3)(4,2,0)(5,3,1)(6,4,2)(7,5,3)(8,4,0)(9,5,1)(10,6,2)(11,7,3)(12,6,0)(13,7,1)(14,8,2)(15,9,3)(16,8,0)(17,9,1)(18,10,2)(19,11,3)[4] Permalink of this calculation is http://gyafun.jp/ln/basmat.cgi?ini=%280%2C0%2C0%29%281%2C1%2C1%29%282%2C2%2C2%29%283%2C3%2C3%29%284%2C2%2C1%29%5B2%5D&max=20&inc=3
 * 1) 2 (0,0,0)(1,1,1)(2,2,2)(3,3,3)(4,2,1)[2]

for Rule 4. "if both Rule 1 and 2 is not applicable", "if neither Rule 1 or 2 is applicable" is better.