User blog:Anpokan/About Introduction to BEAF

Nice to meet you. I'm Anpokan,a Japanese student.

I'm studying BEAF and I found something strange about Multidimensional arrays. http://googology.wikia.com/wiki/Introduction_to_BEAF#Multidimensional_arrays

It says $$\{a,b (1) 1,2\}=\{a, a, \ldots, a, a\}_{\{a, a, \ldots, a, a\}_{\{a, a, \ldots, a, a\}_{._{._.}}}}$$.

How many "a" does the array have? I verified.

Let b,p be 3,5.

$$ \begin{align} \{b,p (1) 1,2\} &= \{3,5 (1) 1,2\} \\ &= \{3,3,3,3,3 (1) \{3,4 (1) 1,2\},1\} \\ &= \{3,3,3,3,3 (1) \{3,3,3,3 (1) \{3,3 (1) 1,2\},1\}\} \\ &= \{3,3,3,3,3 (1) \{3,3,3,3 (1) \{3,3,3 (1) \{3,2 (1) 1,2\},1\}\}\} \\ &= \{3,3,3,3,3 (1) \{3,3,3,3 (1) \{3,3,3 (1) \{3,3 (1) \{3,1 (1) 1,2\},1\}\}\}\} \\ &= \{3,3,3,3,3 (1) \{3,3,3,3 (1) \{3,3,3 (1) \{3,3 (1) 3\}\}\}\} \end{align} $$

The first array has five 3's but the 2nd one has four 3's and the 3rd one has three 3's…

when a nth array makes a n+1th array, p is decreased by one so the number of prime block of the n+1th array will decrease and decrease…

I think such a form($$\{a,b (1) 1,2\}=\{a, a, \ldots, a, a\}_{\{a, a, \ldots, a, a\}_{\{a, a, \ldots, a, a\}_{._{._.}}}}$$) will mislead us with the number of a.