User blog comment:BlauesWasser/Kefts Number/@comment-34610280-20180215042916/@comment-34700793-20180215080349

Define a function A(n)

A(1) = Kefts(3,3,3) = 3^^^4

A(n+1) = Kefts(A(n),A(n),A(n))

SubB = A(1) = 3^^^4

SubA = (3^^^4)^^^(3^^^4+1) = A(2)

Kefts number is ((3^^^4)^^^(3^^^4+1))^^^((3^^^4)^^^(3^^^4+1)+1) = A(3)

Assuming Kefts(a,b,n) = a^^a^^...^^a^^b (n-1 a's) then Kefts number is...

((3^^^3)^^^^2)^^^^2 which is a LOT cleaner.