User blog comment:I am a McCree God/I think I have found how many arrows Graham's Number has./@comment-32783837-20171028131256

Wrong, absolutely wrong. I don't know how you just came up with that, but that's seriously wrong.

g(1) = 3↑↑↑↑3 which is already equal to:

Stage 1. 3

Stage 2. 3^3^3 = 7625597484987

Stage 3. 3^3^3^3^3^...^3^3^3^3^3 with 7625597484987 3s = tritri, which would already take a power tower of trillions of 10s to be able to feasibly express in scientific notation

Stage 4. 3^3^3^3^3^...^3^3^3^3^3 with Stage 3 3s

Stage n. 3^3^3^3^3^...^3^3^3^3^3 with Stage n-1 3s

g(1) is Stage Stage 3.

g(2) = 3 ↑↑ ↑↑ ↑↑ ↑↑... ↑↑ ↑↑ ↑↑ ↑↑3 with g(1) arrows

g(3) =  3 ↑↑ ↑↑ ↑↑ ↑↑... ↑↑ ↑↑ ↑↑ ↑↑3 with g(2) arrows

g(4) =  3 ↑↑ ↑↑ ↑↑ ↑↑... ↑↑ ↑↑ ↑↑ ↑↑3 with g(3) arrows

g(n) =  3 ↑↑ ↑↑ ↑↑ ↑↑... ↑↑ ↑↑ ↑↑ ↑↑3 with g(n-1) arrows

Graham's number is G(64).