User blog comment:Primussupremus/more depth in the expansions and theory of my array notation part 2./@comment-30754445-20170518192340/@comment-31390121-20170521163615

Heres how the notation would actually plan out after I fixed my mistake:

1. 3{3^27 up arrows}3 = a

2. 3{a up arrows}3 = b.

3. 3{b up arrows}3 = c.

So the nth result is a{n-1th result number of up arrows}b.