User blog comment:Wythagoras/Dollar function part 2/@comment-5029411-20130607202808/@comment-10429372-20130608072412

Thanks for your comment. I think I'm going to use a$ = a\(\rightarrow_{a\(\rightarrow_{a\(\rightarrow_{a\(\rightarrow_a\)a}\)a}\)a}\)a with a nests,