User blog comment:Bubby3/BM1 is weaker than expected./@comment-11227630-20180326102019/@comment-11227630-20180326121217

One more step:

From (0,0)(1,1)(2,2)(3,0)(2,2), "bad part" B = (1,1)(2,2)(3,0), "N" = (2,2), "L" = (1,1), "Δ" = (1,0). So (0,0)(1,1)(2,2)(3,0)(2,2)[1] reduces to (0,0)(1,1)(2,2)(3,0)(2,1)(3,2)(4,0)[1].

After deleting the last term, (0,0)(1,1)(2,2)(3,0)(2,1)(3,2)[2] reduces to (0,0)(1,1)(2,2)(3,0)(2,1)(3,1)(4,1)[4].