Talk:Bowers Exploding Array Function

Wait, but isn't \(\lbrace a,b / c \rbrace = \lbrace a \& a \& a \cdots a \& a \& a / c-1\lbrace\) (b times)? Bowers defines it in "legion arrays" quite so. If we say that \(\lbrace a,b / c \lbrace = \lbrace a,\lbrace a,b-1 / c\rbrace / c-1\rbrace,\) it is no better than \(\lbrace a,b,c / 2\rbrace\). I will fix that. Ikosarakt1 (talk) 21:47, January 30, 2013 (UTC)