User blog:Luckyluxiuz/Copy Notation Extension

For example: 3[``4] =  3[3[4]3]3

If the amount of ` s equals 1, then \( m[`n]_1 \) is equal to \(m[n]\)

If the amount of ` s is greater than 1, then \( m[\underbrace{``````` \cdot\cdot\cdot ````}_{p}n]_{o} = m[\underbrace{`````` \cdot \cdot \cdot ``````}_{p \cdot o}n] \)

If the amount of square brackets is greater than 1, then for example: \( m`n = m[\underbrace{`m[``m[ \cdot \cdot [\underbrace{````` \cdot ````}_{o}m [n] m \cdot\cdot\cdot] m] m]}_{o} \)

If the amount of m's is greater than 1, and the amount of ` s are greater than one, then for example: \( m``n = m[``m[````m[\underbrace{```` \cdot \cdot \cdot `````}_{2o}m [n]] \cdot \cdot \cdot ]

I call this the Copyxpansion.

edit: this already exists.

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Copysplosion:

Example: \(m[&n] \) = m[n]

If the amount of ampersands are more than 1, then if the amounts of ` are represented as a superscript number, then \( m[&&n] = \underbrace{m[^{n \uparrow^{m} n}m[^{n \uparrow^{m-1} n}n[^{n \uparrow^{m-2} n}n[\cdot\cdot\cdot [^{n \uparrow^{1} n}[n]}_{m} \cdot\cdot\cdot ]]]

If the amount of brackets are more than 1, then if the amounts of ` and & are represented as superscript, then \( m&&n = \text{the same rule as copyxpansion.} \)

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Copyxpansionsplosion:

Example: \(m[$n] = m[&&m[``n]] \)

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Numbers:

3[```5] = 3[3[3[5]]] = 3[3[33333]] ≈3[\((3.3333 \cdot 10^{33333}\)]

\(10[\underbrace{``````` \cdot\cdot\cdot `````}_{10^{100}}100] = \text{Ceptionexpoogol}\)

\(10[\underbrace{&&&&&&& \cdot\cdot\cdot &&&&&}_{10^{100}}100]\) = \text{Ceptionsploogol}\)

\(10[\underbrace{$$$$$$$ \cdot\cdot\cdot $$$$$}_{10^{100}}100] = \text{Ceptionexpansploogol}\)

\(10[$$100] = \text{Expansploogol}\)

\(10[&&100] = \text{Sploogol}\)

\(10[``100] = \text{Expoogol}\)