User blog comment:Cheetahrock63/Hyper operator notations/@comment-32876686-20171103201341/@comment-31607182-20171103211929

For $$E_{k=1} ^l (k)$$, replace the k with (l + 1 - k); e.g.:

$$ E_{k=1} ^5 (3k+2) = 5^{8^{11^{14^{17}}}} $$

$$ E_{k=1} ^5 (3\cdot(6-k)+2) = 17^{14^{11^{8^{5}}}} $$