User blog comment:SuperSpruce/What do you think the growth rate of the Meameamealokkapowwa oompa is?/@comment-36984051-20190419200104/@comment-35870936-20190420045328

No, it is much higher than that. Hyp cos has done an analysis: https://googology.wikia.org/wiki/User_blog:Hyp_cos/Analysis_-_BEAF,_FGH_and_SGH_(part_2) and https://googology.wikia.org/wiki/User:Hyp_cos/Catching_Function_Analysis_p3

psi(W_W) corresponds to {X,X,2/2} && n.

The limit of {n,n////...//2} is psi(psi_I(0)).

The size of Meameamealokkapoowa oompa is so big that it would go past even pDAN (the limit of which is probably C(e(W+1)) in the catching function). However, it would be beat by sDAN. In his analysis, Hyp cos said that BEAF's growth rate is about nR{0{0{0,,0,,{0}}1*}1} in R function, which corresponds to s(1{1,,,1,,,1,2}2) in SAN (I think).