User blog comment:Tachyonic Encrypter/The Hedera Function/@comment-1782812-20141029222007

I think I get it now. You take x!^(x-1)!^(x-2)!^...^3!^2!^1!, mutliplied by (x-1)!^(x-2)!^(x-3)!^...^3!^2!^1!, multiplied by (x-2)!^(x-3)!^(x-4)!^...^3!^2!^1!, and so on until you're done, then take (x!^(all that))!. I think.

So:

❦(0) = 1

❦(1) = 1

❦(2) = 24

❦(3) ≈ 10^10^58