User blog comment:Eners49/The secret 0th hyper-operator?/@comment-35470197-20180726231426/@comment-35532815-20180730121837

@MilkyWay90 in terms of your function it is not possible, but it may be possible in terms of other functions. Let's assume blatantly that The only way I see to break down the successor function (without it causing any problems) which is x+1 is to do x+(1/y), etc. and iterate that y times. x+(1/y) would be x[-1]y in terms of hyperoperations, or x{-3}y in terms of BEAF. But then again, that ruins the theory that x+y = x?x?x?x?...?x?x?x with y x's. So if we want to do it this way, we have to abandon the way we already look at up-arrows and hyperoperations in general.

So in conclusion, the 0th hyperoperation and below really depends on how you want to look at it since no one has selected one way as the best.

And if you joined Googology Wiki that probably means you're really good at math and you're probably a huge nerd just like I am.

@Fandom User I expected most googologists to be around high-school age, so maybe like 16, 17, etc. and not only will the 10 year olds be too young to share their age, but they will be too young to be googologists; them with all their Sam's Number and the Gigaboomverse and all their other stupid "googolisms."