User blog comment:IAmNotATRex/My Extension to the Fast Growing Hierarchy/@comment-35870936-20180820052650/@comment-36645939-20180821113100

I still don't see how \(F1_{0}(n)\) is only equal to \(f_{\omega+1}(n)\), since the function "layers" the subscript and not the input value in parentheses. In the case of \(F1_{0}(3)\) (one of my examples), this is clear: it's not equal to \(f_{4}(3)\), but instead \(f_{f_{4}(3)}(3)\), where \(f_{4}(3)\) is the subscript.