User blog comment:PsiCubed2/Let's try this again: A simple yes/no poll/@comment-25601061-20180423204855/@comment-30754445-20180423211501

Thank you for your vote. Here is your random number (or at least - a decent approximation of it):

fε₀^ε₀^ε₀^[ε₀^(ω^2+ω) * ω^ω^2](6) (it's in the 61st percentile of the distribution)