User blog comment:Koteitan/Categorizing of the rule sets for all sub versions of bashicu matrix/@comment-11227630-20191122112930

In the All 1 or (1,0,…,0) (ascending modification rule) shown here, if \(a^'_{1j}=0\) then \(a_{1j}=1\). But in the source code, it seems that \(a^'_{1j}=0\) yield \(a_{1j}=0\).