User blog:Alemagno12/An extension of FGH to uncountable ordinals

If everything works out correctly, this hierarchy will be extremely strong.

Define a four-entry version of the FGH as follows: Now, you might be asking:
 * f(0,1,z,w) = z+1
 * f(x+1,1,z,w) = f(x,z,z,w)
 * f(x,y+1,z,w) = f(x,1,f(x,y,z,w),w)
 * If x is a limit ordinal, f(x,1,z,w) = f(x[z],1,z,w)

Well, what's the difference between normal FGH and this version of it?

And this is the difference:
 * If x is an uncountable ordinal, f(x,1,z,w) = f(x[z,w],1,z,w)

Now, I need to explain what this two-entry fundamental sequence is.

[WIP]