User blog comment:B1mb0w/Growth Rate of the S Function/@comment-25601061-20160708203814/@comment-10262436-20160710064433

Your last comment stated  S(n,S(T(0),2,T(0)),1) which equals S(n,S(T(0),3,1),1)  . Are we in agreement on this....?

I just put some results up for T(1).

S(2,T(1),1) = S(2,S(T(0),T(0),1) = S(2,S(T(0),2,1),1)

S(2,S(T(0),1,1),1) = f_w_2(2) = f_e_0(2)

S(2,S(T(0),2,1),1) = f_e_0.2(2) = f_e_0.w(2)

S(3,T(1),1) = S(3,S(T(0),3,1),1) >>   f_e_0(3)

 S(4,T(1),1) = S(4,S(T(0),4,1),1) >>   f_z_0(4)

 S(5,T(1),1) = S(5,S(T(0),5,1),1) >>   f_phi(5,0)(5)