User:Alemagno12/BMS to TON

Let X is a BMS sequence and Y is a BMS element. Then, f(X,Y) = X, but for all n, the nth number of every element of X is replaced with itself plus the nth number of Y.

If X and Y are BMS sequence, then X+Y is concatenation.

Before doing each conversion, convert C(x,C(y,C(z,...))) into C(x,y,z,...).

Up to e0
[WIP]
 * Empty string -> 0
 * (0) -> C(0,0)
 * X -> x: (0)+f(X,(1)) -> C(x,0)
 * X -> C(x,y,z,...,0), Y -> C(a,b,c,...0): X+Y = C(a,b,c,...,x,y,z,...,0)