Hypertriakulus

The hypertriakulus is equal to \(\text{hyper}3\&3\&3 = \text{hyper}\{ 3,3 /2 \}\ = \text{hyper}\{L,1\}_{3,3}\) using the array of operator and BEAF. Since the array of operator solves from left to right, \(\text{hyper}3\&3\&3 = \text{hyper}\{ 3,3,3 \} \& 3 \), a pentational array.