User talk:172.58.111.50

Oh,well....hello!

I can explain how modules work.I had someone else ask me that a while ago.I can tell you all about mBHAN,but I allready had send him a detailed message:

Modules are simply maps.They work similarly to how modules work in computers.You have a lot of different parts and you put them all in a big system.With arrays we have //Ma,b// be a map with exactly a cells.Each cell is connected to every other cell and you can move between them.Every movement you make is called a "switch".//Ma,b// represents a map with a cells and to get the exact value for this expression,you havet to move through b switches.Now to get to the googological part of this:we define \(//M1,b// = //b^{\{n,+\}}b//\) - something that's allready defined,otherwise,if we have more than one cells we have a module with one less cells in every single cell,with the number of switches replaced by the number that we have at that moment.As an example we have //M3,4//.Let's for the sake of simplicity say that,we now what //M1,n// is ..... we call it Cn.We begin to solve //M2,n//,we start at the first switch - inside the switch there's //M1,n//.We allready now that's Cn,next we go to the second swich - there we have //M1,Cn// .... and that's CCn.

You can allready see this ends with CCC.....CCn with n C's.Well,yes and M2 adds 1 to the growth rate of M1.

We now know that //M2,4// = CCCC4,next we begin to solve //M3,4// - at the first switch we start to find //M2,4// inside,we repeat the proces,but having that many switches drawn to the previous module every time,untill it's time to move to the next switch.The number of switches there are increaces the number by which the growth rate increaces.M3 increaces the growth rate by \(\omega\).At this point those modules beyond M3 become very complex to follow examples.Each module with n+1 cells increases the growth rate by \(\omega^\lambda\) for \(\lambda\) is the ordinal for a module with n cells.Overall Modular arrays grow very rapidly - the limit of the function is \(\varepsilon_0\).I hope you now understand,if you have any questions,please ask me and I'll respond when I see it.Boboris02 (talk) 08:33, January 5, 2017 (UTC)