User blog:Kel47/Exploding T notation part 3

First, Let me try to express the notation so far in Terms of the FGH.

$$Tb = 10^b about f_2$$ $$aTb$$ is similar to tetration $$f_3$$ aTb@c@d about $$f_4$$ aTb@..@c with x terms - $$f_x$$ aTb@@c - $$f_\omega$$ aTb@@c@f - $$f_{\omega + 1}$$ aTb@@c@@f - $$f_{2 * \omega }$$ aTb@@@f - $$f_{\omega^2 }$$ aTb(@^@)c - $$f_{\omega^\omega }$$ aTb(@^^@)c - $$f_{\epsilon_0}$$

Going even further...

aTb(@^^@)10@5 = aTb(@^^@)5T10 = aTb(@^^5T10)5T10 = The height of the power tower of @ is 10^^6 $$f_{\epsilon_0+1}$$

aTb(@^^@)10(@^^@)6 First, the 10(@^^@)6 turns into 10(@^^6)6 aTb(@^^@)10(@^@^@^@^@^@)6 aTb(@^^@)10(@^@^@^@^@^6)6 aTb(@^^@)10(@^@^@^@^@^6)6 aTb(@^^@)10(@^@^@^@^@^5)6(@^@^@^@^@^5)6(@^@^@^@^@^5)6(@^@^@^@^@^5)6(@^@^@^@^@^5)6(@^@^@^@^@^5)6 Then the last 5 turns into several copies of (@^@^@^@^@^4), which turns into several copies of (@^@^@^@^@^3), (@^@^@^@^@^2), then finally (@^@^@^@^@). Then you have to keep going down the power tower until you get aTb(@^^@)10@a@b....@z with a GIANT number of @.