User blog comment:B1mb0w/new Alpha Function/@comment-25601061-20150830194544/@comment-1605058-20150830200105

According to your "definition" (which isn't a definition, as it's incomplete), we get \(\alpha(2)=\alpha(2^n)\) for \(n=1\), so this definition suggests there to be 1-1=0 0's after the 1, which is wrong.