User:Vel!/tetrational illion series

Tier 1
Using certain notation H(x) = 103x+3

thousand = H(0) million = H(1) billion = H(2)

Oh actually we can make a table:

And if n = 0,1,2,3,4,5,6,7,8,9, use thousand, million, billion, trillion, quadrillion, quintillion, sextillion, septillion, octillion, nonillion.

Second block
Now we define millillion = H(1000). Then comes milli-million, milli-billion, ..., milli-untrigintiseptingentillion (yes random number), ..., millli-novemnonagintinongentillion = H(1999)

Then bimillillion = H(2000). Then comes bimilli-million, bimilli-billion, etc.

Then trimillillion, quadrimillillion, quintimillillion, sextimillillion, septimillillion, octimillillion, nonimillillion, decimillillion, undeci-, duodeci-, ..., sexquinquagintiduxenti-, ..., novemnonagintinongenti- millillion.

What comes after novemnonagintinongentimilli-novemnonagintinongentillion?

That's a matter for...

Higher
Now temporarily we'll use x-mega-y-milli-z-illion = H(x*1,000,000+y*1,000+z). If any one of them (except z!) is one, they are omitted, and if x or y is zero, they are omitted along with "mega" for x and "milli" for y. If z is zero, it is omitted.

Continue with w-giga-x-mega-y-milli-z-illion, -tera-, peta, exa, zetta, yotta. Now instead of those placeholder SI prefixes, ta-x-ol is used as the root for x-illion. So

tamolillion = H(H(1))

tabolillion = H(H(2))

tatrolillion = H(H(3))

tadecolillion = H(H(10))

tacentolillion = H(H(100))

tamillolillion = H(H(1000))

tatamololillion = H(H(H(1)))

tatobololillion = H(H(H(2)))

tatatamolololillion = H(H(H(H(1))))

tatatatamololololillion = H5(1)

...

(note: if the root for x starts with a vowel, use tal-x-ol instad of ta-x-ol)

Introduction to tetration
Now we can define tetration!

a^^0 = 1

a^^(b+1) = aa^^b

Now define x-illitetration as 10^^(3x+3)