User blog comment:Swooped me in one hit/MCSICKLE/@comment-29310326-20170213182322/@comment-30754445-20170214000756

Sure.

In BEAF:

{10,10,x} = 10 [x arrows] 10

So:

10 ↑↑ ↑↑10 = {10,10,4}

And since your number has 10 ↑↑ ↑↑10 in it, we could write it (exactly) as:

{10,10,{10,10,4}}

In 4-arrays, we could bound this number between:

{4,3,1,2} = 4 [4 ↑↑ ↑↑4 arrows] 4

and

{5,3,1,2} = 5 [5↑↑↑↑↑5 arrows] 5

In Letter Notation:

Jx = 10 [x arrows] 10

So: 10 ↑↑ ↑↑10 = J4

And your number, which has J4 arrows in it, will be JJ4.

Alternatively, we could write JJ4 = K(2+log 4) ~ K2.6, which could be interpreted in BEAF as {10,2.6,1,2} (because for integers, Kn = {10,n,1,2} exactly)