User blog comment:Maxywaxy/Someone tell me if this is right/@comment-35470197-20181109033603/@comment-26941021-20181203002030

i mean i knew that but i thought:

\(f_{2}(n)\) = n times 2, n times

so i then thought

\(f_{3}(n)\) = n times 2, n times, n times

and that's where i messed up.

i was trying to make an equation (like \(f_{0 to 2}(n)\) has.

0 = n+1

1 = 2n

2 =  n*2^n

3 = what i wanted to figure out

so i just defined

\(f_{\omega}(x)\) as \(x*((2^{x})^{x^{x-2}})\)

oops

that would mean dekalum = \(10240^{100000000}\) which is way less than it actually is

or tralum (normally around E3#10) would be 1356 haha

anyway as i said i was trying to work out the formula for \(f_{3}(x)\) but idk if there is one