User blog comment:Nedherman1/About incomputables numbers/@comment-32697988-20180629004537/@comment-5529393-20180629045819

@Alemagno12 That's very much not true. There are a continuum number of uncomputable functions which only take the values 0 and 1, so that are outgrown by the very computable f(x) = x, for instance. What is true is that there are some uncomputable functions that grow faster than all computable functions. But many do not.