User blog comment:Wythagoras/All my stuff/@comment-10429372-20130718073726/@comment-7484840-20130718161151

I see what you're saying, and that functions like the z function will just not be included in the ¥ function because of its tendency to shoot of to infinity.

However, for any finite output possibility for the ¥ function, there will always be a larger possible finite output. This means it's condition for the largest possible output cannot possibly be furfilled and therefore, as with the z function, the ¥ function cannot take on a value.

If the z function works, then the output of the ¥ function makes no sense at all.

If the z function does not work, then neither does the ¥.