User blog:Kel47/Illion Notation part 2

I(x) = 10^(3x+3)

I(1) = 10(3*1+3)=10^6= million

I(10) = 10(3*10+3) = 10^33 = decillion

I(100) = 10(3*100+3) = 10^303 = centillion

I(I(1)) = I(1,000,000) = I(3*1,000,000+3) = I(3,000,003) = milli-millillion

I(x,1) = I(x)

I(x,y) = I(I(x,y-1),y-1)

I(3,2) = I(I(3,1),1) = I(I(3)) = I(10^12) = 10^(3*10^12+3) = picillion

I(5,3) = I(I(5,2),2) = I(I(I(5,1),1),2) = I(I(I(5),2))) = I(I(I(I(5,1),1))) = I(I(I(I(5)))

=I(I(I(10^18) = I(I(10^(3*10^18+3)) = 10^(3*10^(3*10^(3*10^18+3)+3)+3)+3) ~=

10^(3*10^(3*10^(3*10^18)))) > 10^10^10^10^18 > 10^^5 

I(9,4) = I(I(9,3),3) = I(I(I(9,2),2),3) = I(I(I(I(9,1),1),2),3) = I(I(I(10^30),2),3) = I(I(I(I(10^30))),3)

= I(I(I(I(I(I(I(I(10^30)))) ~= 10^10^10^10^10^10^10^10^10^30 > 10^^10