User blog comment:PokémonDude3333/What it would look like if I defined a number/@comment-24923514-20191109233546

A(1) = (3^^^3)^^(3^^^3) = (3^^^3)^^^2

A(n+1) < A(n)*A(n) = A(n)^2, therefore A(n) < A(1)^(2^(n-1))

B(n) = A(999+n), C(n) = B(999+n) = A(2*999+n), ... , ZZ(n) = A((26*27-1)*999+n)

AAA(1) = A(701299) < ((3^^^3)^^^2)^(2^701298) < 3^^^(3^^^(2^(2^701298))) << 3^^^(3^^^(3^^^3))

= 3^^^^4

You almost added a single arrow to and increased the second argument of tritri.