User blog comment:Edwin Shade/The Quicksilver Hierarchy/@comment-28606698-20171023154642

Thus, for example

$$Q_1(3)=Q_{Q_0(3)}^{Q_0(3)}(3)=Q_{f_1(3)}^{f_1(3)}(3)>Q_1(3)$$ since $$f_1(3)>1$$