User blog comment:Googleaarex/My ordinal is smaller!/@comment-5150073-20140922213520/@comment-5029411-20141018235456

$$\phi(\phi_{\chi(M_{M_M})}(0))[3]$$

$$\phi(\phi_{\chi(M_{M_M})}(0))[2] = \phi(\phi_{\chi(M_{\chi(M_M)})}(0))$$

$$\phi(\phi_{\chi(M_{\chi(M)})}(0))$$