User blog comment:Wythagoras/All my stuff/@comment-10429372-20130715145943/@comment-10429372-20130715185145

Well, ¥^1000(1000) is based on recursion around iota I think. I define f(n) = I_x(I_x(I_x(...))) and f(n) is not in the iota set. so Ultimate Wythagoras Number >> Hollom's Number.