User blog comment:Ikosarakt1/Ideas of going past psi(K)/@comment-68.111.90.23-20140625141707/@comment-10429372-20140625191009

Well, if the indescribables Deedlit meant are the \(\Pi^m_n\) indescribables, which is not very likely, but possible, then the n-argument psi function is very, very, strong. (It is quite strong anyway)