User blog comment:Googleaarex/My number is bigger! (Googology Wiki version)/@comment-24509095-20140921170054/@comment-5029411-20140921170518

F_0(n) = (100,100100)(100)(100)...(100)(100)/w n (100)'s

F_x+1(n) = F_x(F_x(...F_x(F_x(n))...))/w n F's

F_a(n) = F_a[n](n)

My number is $$F_{\omega^\omega}(n)$$