User blog comment:Billicusp/Extending ExE to absurd heights/@comment-5529393-20160222033533

I'm not following this notation. You say that { {1} } is a blasphemorgulus, but what do double brackets do in general? One would expect { {a} } to be increasing as the notation a increases, but you say that E100#{ {2} }#100 is equal to E100{ {1{ {1{ {...{ {1} }...} }1} }1} }#100 with 199 ones - this is strange since 2 is much less than 1{ {1{ {...{ {1} }...} }1} }1, notation-wise. The only way I see to make sense of that is to avoid using numbers bigger than 1 before you get to { {2} }, but then { {1{ {1{ {...{ {1} }...} }1} }1} } would not be much bigger than { {1} } at all, it would only be 99 notations after { {1} }. So suffice to say I'm quite unsure of what you are doing.