User blog comment:Ikosarakt1/Ideas of going past psi(K)/@comment-5029411-20140617213739

So chi(1,0) = psi_I(0)

chi(1,a) = psi_I(a)

chi(2,0) = psi_{I_2}(0)

chi(a,0) = psi_{I_a}(0)?