User blog comment:XXxKennyDashxXx/A NEW NOTATION! HBAN./@comment-99.185.0.100-20150806234146/@comment-99.185.0.100-20150806235207

I figured out how to define the second part of EHBAN!

% is the rest of the arguments in an array.

&[a] = 10^^a

&@{1}[a] = &@[a][a]...[a][a] with a [a]s

&@{n}[a] = &@{n-1}{n-1}...{n-1}{n-1}[a] with a {n-1}s

&@{n,%}[a] = &@{n-1,%}{n-1,%}...{n-1,%}{n-1,%}[a] with a {n-1,%}s

&@{1,1,...,1,1,n,%}[a] = &@{1,1,...,1,a,n-1,%}[a]

&@[a][b]# = &@[a-1][&@[a][b-1]#]#

&@[a][1]# = a

&@[1]# = &@#