User blog comment:Ubersketch/W.I.P. Googology Guide/@comment-35470197-20190607225759

In the explanation of ordinal arithmetic, are wrong even under the condintion described in the blog post, because hold.
 * \(n \times m = m\)
 * \(n^m = m\)
 * \(0 \times \omega = 0\)
 * \(0^{\omega} = 0\)
 * \(1^{\omega} = 1\)