User blog:JonnyGamer2002/Reaching j(100)

Circle Function

10 + 10 = 20

10 (+) 10 = 10^^^... (10+10 amount of ^'s) ...^^^10

10 ^ 10 = 1E10

10 (^) 10 = 10^^^... (10^10 amount of ^'s) ...^^^10

• Circles - - can also have circles around them

10 ((^)) 10 = 10^^^... (10^^^... (10^10 amount of ^’s) …^^^10 amount of ^’s) …^^^10

Can also be written as = [10,10] or [2^1] for short (10's are given)

Bracket Function

[2^1] = [10,10] [3^1] = [10, [10, 10] [2^2] = 10,10],[10,10] [5^1] = [10,[10,[10,[10,10]]

[2^1] = [10,10] [3^1] = [10, [10, 10] [2^2] = 10,10],[10,10] [5^1] = [10,[10,[10,[10,10]] You can also do [ [10^10] ^ [10^10] ] - which can be written as |2, 10, 1|


 * 2, 2, 2| |10, 10, 10|

You can also do | |10, 10, 10|, |10, 10, 10|, |10, 10, 10| | Which is written as 3:3 (3 groups of 3, which leads to my next function)

Function Grouping

3:3 can also be written as 3-(f1)-3 --  (explanation later) 10:10:10:10:10 (this works out from right to left)

10:10:10:10:10 will be written as 10_5 or  10-(f2)-5  --  explanation in a moment) 10_10_10 also works right to left

10_10_10 can be written as 10-(f3)-3

J Function

10-(f10)-10 will be written as J1 10-(f 10-(f10)-10)-10 will be written as J2

J3 J10 J(J(J10) - J10,3 J(J(J(J(J(J(J(J(J(J10))))))))) - J10,10 - J>2

J>3 - J10,10,10 - which works as J10,(J10,10) J>10

J>(J>10) --- J>>2 J>(J>(J>10)) --- J>>3 J>>10

J>>>2 --- J>>(J>>10) J>>>3 --- J>>(J>>(J>>10)

J>>>10 --- J<3>10 J<10>10

J<(J<10>10)>10 --- J^2 J<(J<(J<10>10)>10)>10 --- J^3 J^4 J^10

J^(J^10) --- J^^2 J^(J^(J^10)) --- J^^3

J^^10 --- •J-2• = J^(J^(J^(J^(J^(J^(J^(J^(J^(J^(10) J^^^10 --- •J-3• = (J^(J^(J^... •J-(3 - 1)• amount of rows … (J^(J^(10)

J^^^... w/ 10 (*) 10 amount of ^’s …^^^10 --- •J-(10 (*) 10)•

•J-(•J-10•)• --- J°2 •J-(•J-(•J-10)•)• --- J°3

J°10 = j(1) J°J°J°J°J°J°J°J°J°J°10 = j(10)

Jonathan’s Unfathomably Large Number j(100)