User blog comment:Swooped me in one hit/hypothetical situation/@comment-30754445-20170215115300/@comment-30754445-20170215120516

Oh wait... We want to count to a googolplex, so the actual number we need here is:

1+2+3+....+googoplex.

Which is roughly (googolplex)2/2.

The "/2" is completely negligible, but squaring does have an effect:

(googolplex)^2 = (EE100)^2 = (E(2E100)) = EE(100+log 2) ~ EE100.3

So it will take about 10^10^100.3 years (or seconds or centuries or whatever)