User talk:Clarrity

Solution to Question of the Day (March 2, 2018 UTC)
Assuming that by \(10^{100}&10\) and \(10^{101}&10\) you are referring to the higher portions of Bower's BEAF, then I highly doubt under any interpretation of Bower's notation that \(10^{101}&10>\Sigma(101)\), but that rather the inverse holds.

The Busy beaver function outgrows any conceivable computable function, so it is also highly likely that \(\Sigma(100)>10^{100}&10\), and with a bit of patience I'm sure an individual like Deedlit11 or Hyp cos would be able to establish that. Happykitty98 (talk) 15:15, March 2, 2018 (UTC)