User blog:Googleaarex/Okojo-ermine number

f(n) = triangle(10^^n)

f(1,1) = f(54) = triangle(10^^54)

f(1,n+1) = f(1/f(1,n)) = f(1/...f(1,1)...) (n+1 nested)

f(n+1,1) = f(n,54)

f(n+1,m+1) = f(n,1/f(n+1,m))

f(1,1,1) = f(54,1) = f(53,54) = f(52,1/f(53,53))