User blog comment:DrCeasium/Hyperfactorial array notation: Analysis part 2/@comment-5529393-20130527105642/@comment-7484840-20130530152928

In your example (just putting random values in for simplicity's sake), [3...3]w/[4...4]w/[2,2] = [3...3]w/[4,4]w/[1,2] = [3,3,3,3]w/[1,4]w/[1,2] =...(first array evaluates as normal)...=[1]w/[1,4]w,[1,2] = (now the confusing part: the return of the ...) [3...3]w/[1,4]w/[1,2] = [3...3]w/[n,3]w/[1,2] =...(process of the reappearing ... repeats until) ... = [1]w/[1]w/[1,2] = [3...3]w/[4...4]w/[n] =...=[3...3]w/[4...4]w/[1] = [3...3]w/[4...4]w/n = [3...3]w/[4,4,4,...,4,4] with n 4's = and so on. The ...'s only reappear if there is still a w/ after them.

By itself, [1,3]w/10 (random choice) is meaningless, but if you know the starting value, then it is not.