User blog comment:Alejandro Magno/My -illion is bigger!/@comment-4297047-20140923191653/@comment-5029411-20140923194202

Let H**(n) equal n, H**(n,m+1) equal H* (n,n ... n,n) with H**(n,m-1) entries, H**(a,b,…,c,1) equal H**(a,b,…,c), and H**(a,…,b,c,d) equal H**(a,…,b,H**(a,…b,c,d-1)).

Hyper-petihypillion = H******(10)