User:Googleaarex/Hypermathematics

Ok, 2 is base. a+b is addition.

Stage 1:

2+2 = 4, we used base stage 1.

Stage 2:

2, will placed to stage 1 = 8

Stage 4:

2, will placed to stage 3 = 32

On Hypermathematics, a+b = Stage a and 2 will replaced to b on Mathematics.

Stage 1:

2+2 = 8

Stage 2:

8+8 = 8*2^8

Stage 3:

(8*2^8)+(8*2^8) = (8*2^8)*2^(8*2^8)

Stage 8:

\(f^8_2(2) = f^{f_2(2)}_2(2)\)

On Hyper-hypermathematics, a+b = Stage a and 2 will replaced to b on Hypermathematics.

Stage 1:

2+2 = (2+2)+(2+2) on Hypermathematics = 8+8 = 8*2^8

Stage 2:

8*2^8+8*2^8 = \(f^{f^8_2(2)}_2(f^8_2(2))\)

Stage 3:

\(f^{f^{f^8_2(2)}_2(f^8_2(2))}_2(f^{f^8_2(2)}_2(f^8_2(2)))\)

Stage 4:

\(f^{S_3}(S_3)\), \(S_N\) is equal to same at Stage N on Hyper-hyper-mathematics.

Stage 8*2^8:

\(S_{S_1}\)

On Hyper-hyper-hypermathematics, a+b = Stage a and 2 will replaced to b on Hyper-hypermathematics.

Stage 1:

\(S_{S_1}\)