User blog comment:Wythagoras/All my stuff/@comment-10429372-20130718073726

Even ¥(¥(1000)) >> Hollom's Number,

let f(n) be I_x(I_x(...(I_x(I_x(n)))...)) where x is \(I_{I_{1000}(1000)}(1000)\) for example, and f(n) won't be in the iota function for a long, long, long time, and Hollom's Number has taken value, while f(n) is still growing, and Wythagoras's Number is much bigger