User blog comment:Primussupremus/Planck number/@comment-28606698-20170301083601/@comment-32.214.128.232-20170301091147

I think the 4th iteration would have yottaplex^yottaplex arrows, the fifth would have yottaplex^^yottaplex arrows, the 6th yottaplex^(yottaplex arrows)^yottaplex arrows, and so on. Basically take the result of the step 3 steps previous and use that many arrows. Am I correct, OP?