Talk:Introduction to BEAF

Please fix this
The TeX below was included on the article, but I removed it because it contains an error. Please help!

Okay, let's introduce argument #5, first in operator notation and then array notation.


 * \(\underbracket{a\ \{1\}\ b} = a\ \{a\}^{a\ \{a\}^{\ddots^a\iddots}\ a}\ a\)

with \(b\) layers. Extensions to this operator are fairly straightforward, although little complicated to notate:


 * \(\underbracket{a\ \{2\}\ b} = \underbracket{a\ \{1\}\ \underbracket{a\ \{1\}\ \ldots a}}\)
 * \(\underbracket{a\ \{3\}\ b} = \underbracket{a\ \{2\}\ \underbracket{a\ \{2\}\ \ldots a}}\)
 * \(\underbracket{a\ \{1\}^2\ b} = \underbracket{a\ \{\underbracket{a\ \{\ldots a \ldots\}\ a}\}\ a}\)
 * \(\underbracket\underbracket{a\ \{1\}\ b} = \underbracket{a\ \{a\}^\underbracket{a\ \{a\}^\underbracket{\ddots^a\iddots}\ a}\ a}\)

with \(b\) copies/layers/whatever. Our new fifth entry is the number of brackets plus one (so one is default).

In array notation, we can see the pattern more clearly.

&#9729; I want more clouds! &#9925; 11:48, June 8, 2013 (UTC)