User blog comment:MilkyWay90/Extension to the Up-Arrow Notation/@comment-35392788-20180601082756/@comment-31966679-20180602144015

F(3, 1, 3, 2) = F(3, 1, F(3, 1, 3, 1)) = F(3, 1, F(3, 1, 3)) = F(3, 1, 3 ^ 3) = F(3, 1, 27) = 3 ^ 27 = 7.6255975e+12

I may be mistaken, or I might have calculated F(3, 1, 3, 2) in an incorrect way, but to me, it looks like it does terminate.

If I got anything wrong in this reply please let me know.