User blog comment:Mango523WNR/Vista(0,1)=? No.1/@comment-43798125-20200218120319/@comment-30279966-20200218175431

Well, for example, a definition for {a,b,c} for real a,b,c:

{a,b,c} = a^b for (0 <= b < 1)

{a,b,c} = a^c for (0 <= c < 1)

And other rules for b>=1 & c>=1 are the same. Would that work?