User blog comment:Ikosarakt1/Coding strings as ordinals (for Friedman's n(k))/@comment-5029411-20130729191800/@comment-5029411-20130729192352

Uhhhh... A+A = 1+1 = 2

So A+A...A+A = AA = infinity or omega?

AAA = w^w

AAAA = w^w^w

AAAAA = w^w^w^w

B = AA...AA = e(0)

BA...A (n A's) = e(w^^(n-1))

BB = e(e(0))