User blog comment:Hurricane245/Zenna Function/@comment-34876209-20191121141702

If \(Z(1) = 123456789\) but \(Z^x(1) = 123456789\text{ concatenated x times}\), then wouldn't an expression like \(Z^3(3)\) evaluate to \(Z^2(2)\) which would turn into \(Z^1(1) = 123456789\)? Unless \(Z^x\) does not denote recursion, in which case \(Z^3(3)\) would still have to equal \(Z^2(2)\) which would again reduce down to \(Z^1(1) = 123456789\).

Another example: \(Z^4(4) = Z^3(3) = Z^2(2) =Z^1(1) = 123456789\). All of these numbers appear to be the same as 123456789. Please tell me if there's anything I missed.