User blog comment:Simplicityaboveall/Insanely Fast-Growing Functions/@comment-28606698-20171025182658/@comment-28606698-20171103161119

Yes I wrote it in this comment: H(n)\approx f_{\omega+{n-10}}(10) for n>10 and H(n)=10 \uparrow^n 10 for n\le 10.

I compared f_11(10) and f_{\omega+1}(10) as the simpliest example how FGH works in case of a limit ordinal