User blog comment:Nedherman1/New Notation Idea/@comment-30754445-20180718024126/@comment-30754445-20180718040906

By the way, I've calculated fa;a(0), fz;z(0) and fz;z(googol). Oddly enough, fa;a(0) and fz;z(0) are actually equal:

fa;a(0) = fz;z(0) ≈ K98J5050100 ≈ K995051.047 ≈ L100.0324 ≈ M2.0027 ≈ fω+199(5051) ~ fω+2(99)

fz;z(googol) ≈ (1,27)(1,26)E100 ≈ (1,28)2.30102999579 ≈ M27.08711716389 ≈ N2.00066 ≈  fω+27(fω+26(10100))

(as expected, the M29 upper bound holds firm)