User blog:ArtismScrub/A new way to extend the -illions?

Before we begin...
First of all, let's define an "illion function", which we can denote LL(x). Then, LL(x) can be the xth -illion, or 10^(3x+3). So, a thousand would be LL(0), a million would be LL(1), a billion would be LL(2)... a decillion would be LL(10), a centillion would be LL(100), etc.

And define nested uses of the "illion function as LL^n(x), so a nanillion, for example, being LL(LL(2)), could be written as LL^2(2).

The gist of the extension
Now for the extension. Introducing the -x-et suffix series.

Start with -met, the first suffix. x-illionmet would just be LL^1(x), a degenerate case.

But -duet, the second suffix, is where it starts. x-illionduet would be LL^2(x), so a billionduet would be LL^2(2), or a nanillion, mentioned earlier.]

Then -tret, the third suffix. x-illiontret would be LL^3(x).

etc.

Some thoughts, the major purpose & uses of this
Now, I can guess what you're thinking about this. "That's cool, but it doesn't allow for specific -illions." And you're right, but on a scale as large as the -illiontetrets or beyond, in any conventional system, the real name for each -illion would be so long that fully pronouncing it would take years, to say the least. So, this can make for decent approximations in -illion names. Plus, you can just say "x-illion y-illionduet" to mean the (x y-illion)-th illion, and so on.

The rest of the -ets
x-illiontetret = LL^4(x)

x-illionpentet = LL^5(x)

x-illionhexet = LL^6(x)

x-illionheptet = LL^7(x)

x-illionoctet = LL^8(x)

x-illionennet = LL^9(x)



x-illiondeket = LL^10(x)

x-illionhendeket = LL^11(x)

x-illiondodeket = LL^12(x)

x-illiontrideket = LL^13(x)

x-illiontetradeket = LL^14(x)

x-illionpentadeket = LL^15(x)

x-illionhexadeket = LL^16(x)

x-illionheptadeket = LL^17(x)

x-illionoctodeket = LL^18(x)

<p style="font-weight:normal;">x-illionennedeket = LL^19(x)

<p style="font-weight:normal;">

<p style="font-weight:normal;">x-illionicoset = LL^20(x)

<p style="font-weight:normal;">x-illionicosihet = LL^21(x)

<p style="font-weight:normal;">x-illionicosiduet = LL^22(x)

<p style="font-weight:normal;">x-illionicositret = LL^23(x)

<p style="font-weight:normal;">...

<p style="font-weight:normal;">x-illiontriacontet = LL^30(x)

<p style="font-weight:normal;">x-illiontriaconta(n)et = LL^[30+n](x) where (n)et can mean:

<p style="font-weight:normal;">n=1 = -het

<p style="font-weight:normal;">n=2 = -duet

<p style="font-weight:normal;">n=3 = -tret

<p style="font-weight:normal;">n=4 = -tetret

<p style="font-weight:normal;">n=5 = -pentet

<p style="font-weight:normal;">n=6 = -hexet

<p style="font-weight:normal;">n=7 = -heptet

<p style="font-weight:normal;">n=8 = -octet

<p style="font-weight:normal;">n=9 = -ennet

<p style="font-weight:normal;">

<p style="font-weight:normal;">x-illiontetracontet = LL^40(x)

<p style="font-weight:normal;">x-illiontetraconta(n)et = LL^[40+n](x)

<p style="font-weight:normal;">x-illionpentacontet = LL^50(x)

<p style="font-weight:normal;">x-illionpentaconta(n)et = LL^[50+n](x)

<p style="font-weight:normal;">x-illionhexacontet = LL^60(x)

<p style="font-weight:normal;">x-illionhexaconta(n)et = LL^[60+n](x)

<p style="font-weight:normal;">x-illionheptacontet = LL^70(x)

<p style="font-weight:normal;">x-illionheptaconta(n)et = LL^[70+n](x)

<p style="font-weight:normal;">x-illionoctacontet = LL^80(x)

<p style="font-weight:normal;">x-illionoctaconta(n)et = LL^[80+n](x)

<p style="font-weight:normal;">x-illionennacontet = LL^90(x)

<p style="font-weight:normal;">x-illionennaconta(n)et = LL^[90+n](x)

<p style="font-weight:normal;">

<p style="font-weight:normal;">x-illionhectet = LL^100(x)

<p style="font-weight:normal;">x-illionhecto(m)et = LL^[100+m](x) where m can be any of the -ets between -het and -ennacontaennet

<p style="font-weight:normal;">x-illion(l)hectet = LL^100l(x) where l can be:

<p style="font-weight:normal;">-do- = 2

<p style="font-weight:normal;">-tre- = 3

<p style="font-weight:normal;">-tetra- = 4

<p style="font-weight:normal;">-penta- = 5

<p style="font-weight:normal;">-hexa- = 6

<p style="font-weight:normal;">-hepta- = 7

<p style="font-weight:normal;">-octa- = 8

<p style="font-weight:normal;">-ennea- = 9

<p style="font-weight:normal;">x-illion(l)hecto(m)et = LL^[100l+m](x)

<p style="font-weight:normal;">

<p style="font-weight:normal;">x-illionkilet = LL^1,000(x)

<p style="font-weight:normal;">x-illionkilo(a)et = LL^[1,000+a](x) where a is anything between -het and the 999th -et

<p style="font-weight:normal;">x-illion(l)kilet = LL^1,000l(x)

<p style="font-weight:normal;">x-illion(l)kilo(a)et = LL^[1,000l+a](x)

<p style="font-weight:normal;">

<p style="font-weight:normal;">x-illionmeget = LL^1,000,000(x)

<p style="font-weight:normal;">x-illionmega(b)et = LL^[1,000,000+b](x) where b is anything between -het and the 999999th -et

<p style="font-weight:normal;">x-illion(l)meget = LL^1,000,000l(x)

<p style="font-weight:normal;">x-illion(l)mega(b)et = LL^[1,000,000l+b](x)

<p style="font-weight:normal;">

<p style="font-weight:normal;">continue on that similar pattern with -giget, -teret, -petet, -exet, -zettet, -yottet, and perhaps through whatever extended SI prefix system you prefer to use.